What is the remainder when $3 x^{2} + 4 x - 5$ is divided by $(x - 1)$ .

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Solution

${3 x}^{2} + 4 x = 5$
Remainder when divided by $(x - 1)$
$\Rightarrow 3 {(1)}^{2} + 4 (1) - 5 = 3 + 4 - 5 = 2$

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p (x) = 2 x^{3} - 3 x^{2} + 4 x - 5

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