Question

What is the remainder when ${}_{32}{33}^{34}$ is divided by 7?

• A. 4
• B. 2
• C. 3
• D. 1

Answer 1

The correct option is D 1

If $\frac{{32}^{{33}^{34}}}{7}=\frac{(4{)}^{{33}^{34}}}{7}=\frac{(33{)}^{34}}{6}=\frac{(3{)}^{34}}{6}=\frac{\left(3\right)}{2}=\frac{(4{)}^3}{7}$
then remainder =1