What is the remainder, when
$(4 x^{3} - 3 x^{2} + 2 x - 1)$ is divided by (x+2)?

-49

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-30

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Solution

The correct option is A -49
$x + 2) ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 4 x^{3} - 3 x^{2} + 2 x - 1 (4 x^{2} - 11 x + 24 4 x^{3} + 8 x^{2} - - - - - - - - - - - - - - - 11 x^{2} + 2 x - 11 x^{2} - 22 x - - - - - - - - - - - - - 24 x - 1 24 x + 48 - - - - - - - - - - - - - - 49$
Hence,
$The remainder is - 49$

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Similar questions

p (x) = 4 x^{3} - 3 x^{2} + 2 x - 4

x - 1

4 x^{3} - 3 x^{2} + 2 x - 4

x + 3

4 x^{3} - 3 x^{2} + 2 x - 4

x + \frac{1}{2}

Statement1: The polynomial $P (x) = 4 x^{3} - 3 x^{2} + 5 x - 6$ when divided by $x - 1$ gives zero as the remainder.

Statement2: $(x - 1)$ is a factor of the polynomial $P (x) = 4 x^{3} - 3 x^{2} + 5 x - 6$ .

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