What is the resistance under normal working conditions of a 240V electric lamp rated at 60W? If 2 suchlamps are connectedin seriesacrossa 240V mains supply explain why each one appearslessbright.

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Solution

Dear student,

$P = V^{2} / R R = V^{2} / P R = (240)^{2} / 60 R = 960 ohm$

For the second part of question,
The power output of a lamp depends upon the voltage across it. In series connection the voltage is divided and less voltage appears across each lamp. Hence each one appears less bright.

Regards.

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What is the resistance under normal working conditions of a 240V electric lamp rated at 60W? If 2 suchlamps are connectedin seriesacrossa 240V mains supply explain why each one appearslessbright.

Dear student, P=V2/R R=V2/P R=(240)2/60 R=960 ohm For the second part of question, The power output of a lamp depends upon the voltage across it. In series connection the voltage is divided and less voltage appears across each lamp. Hence each one appears less bright. Regards.