Question

What is the resultant capacitance between points A and B?

• A. 51 $\mu$F
• B. 102 $\mu$F
• C. 204 $\mu$F
• D. 408 $\mu$F

Answer 1

The correct option is C 204 $\mu$F

Let $C1=200\mu F$ $C2=20\mu F$ and $C3=5\mu F$

In the given circuit $\left(C2seriesC3\right)||C1$

$\therefore C_{eq}=\left(\frac{200\times 5}{200+5}\right)+200$

$\therefore C_{eq}=\frac{1000+200\times 205}{205}$

$\therefore C_{eq}=204.87\mu F$

Therefore the resultant capacitance between A and B is $C)204\mu F$