What is the resultant polynomial obtained when the given binomials $(a^{3} - c^{2})$ and $(51 c b^{2} + 14 a b c)$ are multiplied?

51 c b^{2} a^{3} - 51 c^{3} b^{2} - 14 a^{4} b c - 14 a b c^{3}

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51 c b^{2} a^{3} - 41 c^{3} b^{2} - 14 a^{4} b c + 14 a b c^{3}

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51 c b^{2} a^{3} - 51 c^{3} b^{2} + 14 a^{4} b c - 14 a b c^{3}

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51 c b^{2} a^{3} - 41 c^{3} b^{2} - 14 a^{4} b c + 14 a b c^{3}

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Solution

The correct option is C $51 c b^{2} a^{3} - 51 c^{3} b^{2} + 14 a^{4} b c - 14 a b c^{3}$
In the given question, a binomial is multiplied with a binomial.
$(a^{3} - c^{2})$ $(51 c b^{2} + 14 a b c)$
$= 51 c b^{2} a^{3} - 51 c^{3} b^{2} + 14 a^{4} b c - 14 a b c^{3}$

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What is the resultant polynomial obtained when the given binomials (a3−c2) and (51cb2+14abc) are multiplied?

The correct option is C 51cb2a3−51c3b2+14a4bc−14abc3In the given question, a binomial is multiplied with a binomial. (a3−c2) (51cb2+14abc) =51cb2a3−51c3b2+14a4bc−14abc3

What is the resultant polynomial obtained when the given binomials $(a^{3} - c^{2})$ and $(51 c b^{2} + 14 a b c)$ are multiplied?

The correct option is C $51 c b^{2} a^{3} - 51 c^{3} b^{2} + 14 a^{4} b c - 14 a b c^{3}$
In the given question, a binomial is multiplied with a binomial.
$(a^{3} - c^{2})$ $(51 c b^{2} + 14 a b c)$
$= 51 c b^{2} a^{3} - 51 c^{3} b^{2} + 14 a^{4} b c - 14 a b c^{3}$