Question

What is the separation energy (in eV) for electron present in the first excited state of $B{e}^{3+}?$

• A. 13.6 eV
• B. 27.2 eV
• C. 40.8 eV
• D. 54.5 eV

Answer 1

The correct option is D 54.5 eV

$B{e}^{+3}$ $z=4$

first excited state $n=2$

$En=-13.6\frac{z^2}{n^2}$

$=0-(-13.6\times \frac{4^2}{2^2})=54.4eV$