What is the separation m1m2- Given v-105 ms-1- B-2T

The correct option is A 2 cm r=mvqB q is same for both isotopes. r_1r_2=m_1m_2 where m_1 and m_2 are masses of chlorine isotopes. ...

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Standard XII

Mathematics

Definition of Relations

What is the s...

Question

What is the separation $m_{1} m_{2}$ ? Given $v = 10^{5} m s^{- 1}, \to B = 2 T$

1 c m

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2 c m

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0.5 c m

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none

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Solution

The correct option is A $2 c m$

$r = \frac{m v}{q B}$

q is same for both isotopes.
$\frac{r_{1}}{r_{2}} = \frac{m_{1}}{m_{2}}$ where $m_{1}$ and $m_{2}$ are masses of chlorine isotopes.
$m_{1} = 35$ ; $m_{2} = 37$
$r_{1} = \frac{m_{1} v}{q B} = \frac{(35 \times 1.6 \times 10^{- 27}) \times 10^{5}}{1.6 \times 10^{- 19} \times 2} = 17.5 \times 10^{- 3} m = 17.5 c m$
$∴ \frac{17.5}{r_{2}} = \frac{35}{37}$
$\Rightarrow r_{2} = \frac{37}{2} = 18.5 c m$
Separation between $m_{1}$ and $m_{2}$ : $2 (r_{2} - r_{1}) = 2 \times (18.5 - 17.5) = 2 c m$

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What is the separation m1m2? Given v=105ms−1,→B=2T

The correct option is A 2cmr=mvqBq is same for both isotopes.r1r2=m1m2 where m1 and m2 are masses of chlorine isotopes.m1=35; m2=37r1=m1vqB=(35×1.6×10−27)×1051.6×10−19×2=17.5×10−3m=17.5cm∴17.5r2=3537⇒r2=372=18.5cmSeparation between m1 and m2: 2(r2−r1)=2×(18.5−17.5)=2cm

What is the separation $m_{1} m_{2}$ ? Given $v = 10^{5} m s^{- 1}, \to B = 2 T$