Question

What is the shape of $Fe(CO{)}_5$ molecule ? Given that its dipole moment = 0.

• A. Tetrahedral
• B. Octahedral
• C. Trigonal bipyramidal
• D. Square pyramidal

Answer 1

The correct option is C Trigonal bipyramidal

In $Fe(CO{)}_5$, as $CO$ is a strong field ligand, then electron pairing occurs against the Hund's rule.
So, the $Fe$ atom is $ds{p}^3$ hybridised therefore shape of molecule is trigonal bipyramidal.
$Fe$ atom in $Fe(CO{)}_5$.
As it is symmetrical molecule, therefore, its dipole moment $\left(\mu \right)$ is zero.