Question

What is the shape of $Xe{F}_3^{+}$?

• A. Trigonal planar
• B. Pyramidal
• C. Bent T-shaped
• D. See-saw

Answer 1

The correct option is C Bent T-shaped

In the compound $Xe{F}_3^{+}$,
Total number of valence electron pairs on $Xe=5$
Number of lone pairs on $Xe=2$
Number of sigma bonds $=3$
Steric number $=5$
Hybridization $=s{p}^{3}d$
Shape of the molecule with $s{p}^{3}d$ hybridization and two lone pairs is bent $T-$shaped.


Thus, option (c) is the correct answer.