What is the shape represented by arg 3z-6-3i-2z-8-6i-4-

arg 3z 6 3i 2z 8 6i =π #160; 4 z=x+iy tan ^ 1 ( 3x+3iy 6 3i 2x+2iy 8 6i ) =π #160; 4 3x+3iy 6 3i 2x+2iy 8 6i =1 3x 6+3i ...

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Polar Representation of a Complex Number

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Question

What is the shape represented by arg $\frac{3 z - 6 - 3 i}{2 z - 8 - 6 i} = \frac{π}{4} ?$

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arg (\frac{3 z - 6 - 3 i}{2 z - 8 - 6 i}) = \frac{π}{4}

| z - 3 + 4 i | = 3.

a r g (\frac{z - 6 - 3 i}{z - 8 - 6 i}) = \frac{π}{4}

(\frac{z - 2}{z - 4}) = \frac{π}{3}

a r g (z - 3 i) = 3 π / 4

a r g (2 z + 1 - 2 i) = π / 4

arg (z - 3 i) = \frac{3 π}{4}

arg (2 z + 1 - 2 i) = \frac{π}{4}

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