What is the SI unit of gravitational constant G?

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Solution

The value of gravitational constant G is $\frac{F r^{2}}{m_{1} m_{2}} = \frac{N e w t o n x {(m e t r e)}^{2}}{(k i \log r a m) x (k i \log r a m)} = \frac{N m^{2}}{k g^{2}} = N m^{2} k g^{- 2}$ .
Hence, SI unit of gravitational constant is $N m^{2} k g^{- 2}$ .

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