What is the slope of a chord centered at (3, 2) in the circle x2 + y2 = 25
-3/2
Here the key point is that any chord of a circle is perpendicular to the radius passing through its midpoint P as shown in the figure
i.e., if M is midpoint of AB then ∠APO = 90∘
In the given question, slope of radius through P = (2−0)(3−0)=(23)
∴ Slope of chord AB = (−32)