What is the slope of a line perpendicular to $2 y = - 6 x - 10$ ?

- 3

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3

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- \frac{1}{3}

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\frac{1}{3}

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Solution

The correct option is D $\frac{1}{3}$
Given equation is $2 y = - 6 x - 10$
Comparing with $y = m x + c$ ,
the slope of the given line is $- 3$ .
For perpendicular lines, we know $m_{1} \times m_{2} = - 1$ , hence
The negative reciprocal for the perpendicular is $\frac{1}{3}$ .

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