Question

What is the slope of a line whose inclination with the positive direction of x axis is ${120}^{\circ }$ ?

Answer 1

Here $\theta ={120}^{\circ }$
$\therefore Slope=\tan \theta =\tan {120}^{\circ }=\tan ({180}^{\circ }-{60}^{\circ })=-\tan {60}^{\circ }=-\sqrt{3}$