What is the slope of the line perpendicular to the equation $y = 3 x + 2$ ?

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Solution

Answer
$m_{2} = - \frac{1}{3}$ the second line's slope
Explanation :
$y = 3 x + 2$ your explanation
$y = m x + a$ general syntax for linear equations
m gives slope
slope of the line $y = 3 x + 2$ is 3
product of the perpendicular lines is $m_{1} . m_{2} = - 1$
$3. m_{2} = - 1$
$m_{2} = \frac{1}{3}$ the second lines's slope
The slope is 3 the slope perpendicular to its $- \frac{1}{3}$

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(i) Is the line 3x + 4y + 7 = 0 perpendicular to the line 28x - 21y + 50 = 0 ?

(ii) Is the line x - 3y = 4 perpendicular to the line 3x - y = 7 ?

(iii) Is the line 3x + 2y = 5 parallel to the line x + 2y = 1 ?

(iv) Determine x so that the slope of the line through (1, 4) and (x, 2) is 2.

y = 6 x + 7

f (x) = 3 x - 1

y = f^{- 1} (x)

y = f (x)

n p

2 y - 3 x = 4

3 x + 4 y - 7 = 0

x - y + 2 = 0

3 x + y - 10 = 0

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