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Question

What is the slope of the line perpendicular to the equation $$ y = 3x + 2 $$ ? 


Solution

Answer 
$$m_{2} = - \dfrac{1}{3}$$ the second line's slope 
Explanation :
$$ y = 3x + 2 $$ your explanation 
$$ y = mx + a $$ general syntax for linear equations 
m gives slope 
slope of the line $$ y = 3x + 2 $$ is 3 
product of the perpendicular lines is $$ m_{1} .m _{2} = - 1 $$ 
$$3. m_{2}  = -1 $$
$$m_{2} = \dfrac{1}{3}$$ the second lines's slope 
The slope is 3 the slope perpendicular to its  $$-\dfrac{1}{3}$$

Mathematics

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