Question

# What is the slope of the line perpendicular to the equation $$y = 3x + 2$$ ?

Solution

## Answer $$m_{2} = - \dfrac{1}{3}$$ the second line's slope Explanation :$$y = 3x + 2$$ your explanation $$y = mx + a$$ general syntax for linear equations m gives slope slope of the line $$y = 3x + 2$$ is 3 product of the perpendicular lines is $$m_{1} .m _{2} = - 1$$ $$3. m_{2} = -1$$$$m_{2} = \dfrac{1}{3}$$ the second lines's slope The slope is 3 the slope perpendicular to its  $$-\dfrac{1}{3}$$Mathematics

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