Question

What is the smallest number that is completely divisible by $24$ and $32$?

• A. $96$
• B. $48$
• C. $120$
• D. $144$

Answer 1

The correct option is A $96$

Prime factorisation of $24$ and $32$ is as follows:
$24=2\times 2\times 2\times 3$
$32=2\times 2\times 2\times 2\times 2$

So, LCM of $24$ and $32$ is $=2\times 2\times 2\times 2\times 2\times 3=96.$

$96$ is a number that is completely divisible by both $24$ and $32$.
It is worth noting that $96$ has all the factors of $24$ and $32.$