What is the smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29 and 34 respectively?
A
1406
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B
1606
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C
1394
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D
1404
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Solution
The correct option is C 1394
∴ L.C.M = 5 × 2 × 2 × 5 × 7 × 2
= 1400
Given, the smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29 and 34 respectively. ∵ 20 - 14 = 25 - 19 = 35 - 29 = 40 - 34 = 6
Here, the difference is equal. So, 6 should be subtracted from the LCM to get the number. ∴ The smallest number =L.C.M−6 =1400−6=1394