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Question

What is the smallest number which when increased by 5 is divisible by 36, 63 and 108?


A

756

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B

751

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C

753

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D

754

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Solution

The correct option is B

751


Calculate the LCM of 36, 63 and 108 which would come out to be 756, so the smallest number is 751 which when increased by 5 is 756.


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