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Question

What is the solubility of a sparignly soluble salt, PbSO4 in 0.01 M Na2SO4 solution ?
(Ksp for PbSO4=1.6×108)

A
1.6×106mol L1
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B
2.6×109mol L1
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C
3.5×107mol L1
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D
0.4×109mol L1
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Solution

The correct option is A 1.6×106mol L1
PbSO4 is a sparingly soluble salt , whereas Na2SO4 is a highly soluble salt.
Let the solubility of PbSO4 be s. Then

PbSO4Pb2++SO24
t=teq cs s s

Sodium sulphate is a strong electrolyte and is completely ionised. It shall provide SO24 ion concentration= 0.01 M.

[Pb2+]=s
[SO24]=(s+0.01) M

Ksp=[Pb2+][SO24]=s×(s+0.01)

Since Na2SO4 is a highly soluble .So s+0.010.01, because of the sparingly soluble salt (PbSO4) where Ksp<<103
Given Ksp=1.6×108
1.6×108=0.01×s
or
s=1.6×1080.01=1.6×106mol L1

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