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Question

What is the solubility of AgCl in 0.20M NH3?


Given: Ksp(AgCl)=1.7×1010 M2, K1=[Ag(NH3)+]/[Ag+][NH3]=2.33×103M1 and K2=[Ag(NH3)+2]/[Ag(NH3)+][NH3]=7.14×103M1

A
9.6×103
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B
19.2×103
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C
15.6×104
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D
31×104
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Solution

The correct option is A 9.6×103
AgCl(s)Ag++ClKsp
Ag++2NH3Ag(NH3)2+K1×K2
AgCl(s)+2NH3Ag(NH3)2++Cl
0.2
0.22x x x
K=x2(0.22x)=KspK1K2=0.002828
x0.22x=0.05318
x=0.009613
Solubility =9.6×103M

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