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Question

What is the solubility of Al(OH3),Ksp=1×1033, in a solution having pH=4?

A
6×103M
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B
106M
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C
1.5×104M
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D
2.47×109M
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Solution

The correct option is C 2.47×109M
The solubility equilibrium of Al(OH)3 is
Al(OH)3 Al+3 + 3OH
Therefore x=1, y=2 and Ksp=[Al+3]×[OH] = 27S4
S = (103327)1/4
Therefore S= 2.47×109M in mol dm3

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