What is the solution of the pair of linear equation 2x+y=5,4x+2y=10.
The given system of equations is:
2x+y–5=0
4x+2y–10=0
The above equations are of the form
a1x+b1y+c1=0
a2x+b2y+c2=0
Here, a1 = 2, b1 = 1, c1 = −5
a2 = 4, b2 = 2, c2 = −10
So according to the question, we get
a1a2 = 24 = 12
b1b2 = 12
c1c2 = −5−10= 12
⇒ a1a2 = b1b2 = c1c2
Hence, we can conclude that the given system of equation has infinity many solutions.