wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the solution set of the equation x3−x2+x−1>0?

A
x < -1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
-1 < x < 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x > 1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x > 0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C x > 1
Best way to solve this problem is by simply assuming some values for x.
Put x = 2, then x3x2+x1=5>0, which is true.
Hence, option (a) and (b) are eliminated.
Put x = 1, then x3x2+x1=0 is not greater than 0, hence option (d) is eliminated.
Option (c) is correct answer.

Alternative Approach:
x3x2+x1>0
x2(x1)+(x1)>0
(x2+1)(x1)>0
As, x2+1>0 for all x, so, x > 1.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Inequations II
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon