What is the solution to the system: 2x + 3y = 1 and -x + y = -3?

(2, 1)

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(-2, -1)

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(-2, 1)

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(2, -1)

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Solution

The correct option is D
(2, -1)

2x + 3y = 1 _(1)

-x + y = -3 (2)

Multiplying equation (2) by 2

-2x + 2y = -6 _(3)

Adding (1) and (3), we get

5y = -5

y = -1

Plugging the value of y in equation (2)

-x - 1 = -3

x = 2

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