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Standard XII

Mathematics

Sum of Coefficients of All Terms

What is the s...

Question

What is the specific heat of the substance in solid phase?

\frac{4}{3} k J (k g K)^{- 1}

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\frac{3}{4} k J (k g K)^{- 1}

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\frac{40}{3} k J (k g K)^{- 1}

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1 k J (k g K)^{- 1}

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Solution

The correct option is A $\frac{4}{3} k J (k g K)^{- 1}$
Heat supplied between time 0 min to 1 min is $q = 10 \times 1 = 1 K J$
$Δ T = 10 - (- 5) = 15^{o} C$
so $Q = 10 = 0.5 \times c \times 15$
$c = \frac{4}{3} k J k g^{- 1} k^{- 1}$

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Similar questions

A substance is in the form of a solid at 0 °C. The amount of heat added to this substance and the temperature of the substance are plotted on the graph.

Fig, 11.9 Amount of heat (in Joule)

If the specific heat capacity of the solid substance is 500 J/kg °C, find from the graph; the specific Latent heat of fusion of the substance in the liquid state.

106.25 J

of heat energy is supplied to a solid of specific heat capacity

0.8 J g^{- 1} C^{- 1}

. Its temperature changes by

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. The mass of the substance is

Q. Consider the following statements.

1.

Specific heat capacity is the amount of heat required to raise the temperature of

1 k g

of a substance through

1

kelvin.

2.

The SI unit of specific heat capacity is

J k g^{- 1} K^{- 1}

and in CGS it is

c a l g^{- 1}^{\circ} C^{- 1}

3.

Thermal capacity is the amount of heat required to raise the temperature of a given amount of substance through

1

kelvin.
Which of the statements given above are correct?

Q. Specific heat capacity of a substance A is

3.8 J g^{- 1} K^{- 1}

and of substance B is

0.4 J g^{- 1} K^{- 1}

is a good conductor of heat ?

Specific heat capacity of a substance A is $3.8 J g^{- 1} K^{- 1}$ and of the substance B is $0.4 J g^{- 1} K^{- 1}$ . Which substance is a good conductor of heat? How did you arrive at your conclusion ?

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What is the specific heat of the substance in solid phase?

The correct option is A 43kJ(kgK)−1Heat supplied between time 0 min to 1 min is q=10×1=1 KJΔT=10−(−5)=15oCso Q=10=0.5×c×15c=43 kJ kg−1 k−1

The correct option is A $\frac{4}{3} k J (k g K)^{- 1}$
Heat supplied between time 0 min to 1 min is $q = 10 \times 1 = 1 K J$
$Δ T = 10 - (- 5) = 15^{o} C$
so $Q = 10 = 0.5 \times c \times 15$
$c = \frac{4}{3} k J k g^{- 1} k^{- 1}$