What is the square root of $(2 x + 3)^{2} - 24 x$ ?

(3x + 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x +6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2x + 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2x – 3)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
(2x – 3)

$\sqrt [(2 x + 3)^{2} - 24 x] = \sqrt [4 x^{2} + 12 x + 9 - 24 x]$

= $\sqrt [4 x^{2} - 12 x + 9]$

= $\sqrt (2 x - 3)^{2}$

= (2x – 3)

Suggest Corrections

Similar questions

x^{4} + 6 x^{3} + 17 x^{2} + 24 x + 16

x^{2} + 3 x + 4

4 + 25 x^{2} - 12 x - 24 x^{3} + 16 x^{4}

4 x^{2} + 24 x + 32

Square root of 1024 is 32.

4 + 25 x^{2} - 12 x - 24 x^{3} + 16 x^{4}

Join BYJU'S Learning Program