What is the square root of (4x2–361)(4x2+12x+9)(64x2–5776) ?
√[(4x2–361)(4x2+12x+9)(64x2–5776)]=√[(2x−19)(2x+19)(2x+3)2(8x–76)(8x+76)]
=√[(2x−19)(2x+19)(2x+3)24(2x−19)4(2x+19)]
= √[42(2x−19)(2x+19)(2x+3)2(2x–19)(2x+19)]
= 4(2x–19)(2x + 19)(2x + 3)
= 4(4x2–361)(2x+3)