What is the standard form of the quadratic equation :
$n - \frac{7}{n} = 4$

n^{2} + 4 n - 7 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n^{2} - 4 n - 7 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

n^{2} - 4 n + 7 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $n^{2} - 4 n - 7 = 0$
Given,
$n - \frac{7}{n} = 4$
$\Rightarrow \frac{n^{2} - 7}{n} = 4$
$\Rightarrow n^{2} - 7 = 4 n$
$\Rightarrow n^{2} - 4 n - 7 = 0$

Suggest Corrections

Similar questions

n^{2} + 4 n = 0

x^{2} + n x + n = 0, n ϵ I

n^{2} - 4 n

ω

(2 - ω) (2 - ω^{2}) + 2 (3 - ω) (3 - ω^{2}) + . . . + (n - 1) (n - ω) (n - ω^{2})

(n^{2} + \frac{1}{n^{2}}) - 4 (n + \frac{1}{n}) + 6

Join BYJU'S Learning Program