Question

What is the stopping potential when the metal with work function 0.6 eV is illuminated with the light of 2 eV

• A. 2.6 V
• B. 3.6 V
• C. 0.8 V
• D. 1.4 V

Answer 1

The correct option is D

1.4 V

$V_0=\frac{(E-W_0)}{e}=\frac{(2eV-0.6eV)}{e}=1.4V$