Question

What is the structure associated with $PB{r}_5$ in ionic solid state?

• A. Trigonal bipyramidal
• B. Tetrahedral
• C. Octahedral
• D. Both $\left(b\right)$ and $\left(c\right)$

Answer 1

The correct option is B Tetrahedral

$PB{r}_5$(solid state) $\to$ $[PB{r}_4{]}^{+}$ + $[Br{]}^{-}$
$s{p}^3$
Tetrahedral
Thus, in solid state $PB{r}_5$ convert into $[PB{r}_4{]}^{+}$ $[Br{]}^{-}$, which have $s{p}^3$ hybridization i.e Tetrahedral in structure.