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Question

What is the structure of XeOF4 ?


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Solution

Step 1: Hybridization:

  • Hybridization is defined as the process of intermixing of the orbitals of slightly different energies so as to redistribute their energies, resulting in the formation of a new set of orbitals of equivalent energies and shape.”

Step 2: Formula used for calculation:

  • Stericnumber=12V+M-C+A
  • Where V is the number of valence electrons of the central atom, M is the monovalent electron, C is the positive charge and A represents the negative charge.

Step 3: Calculation for Hybridisation of XeOF4:

  • The total number of valence electrons in XeOF4 is 8 and there are 4 monovalent atoms.
  • Stericnumber=128+4=12×12Stericnumber=6
  • The Steric number is 6, thus the hybridization of XeOF4 is sp3d2.

Step 4: Structure and shape of XeOF4:

  • The xenon (Xe) atom must bond with the four fluorine (F)atoms into four single bonds and double-bonded with an oxygen atom (O).
  • It has one lone pair of electrons.
  • As per VSEPR theory, sp3d2 has a square pyramidal shape.
  • Therefore, the Xenon oxyfluoride(XeOF4) is square pyramidal in shape with sp3d2 hybridization.
  • The structure of XeOF4 is given below:

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