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B
144
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C
141
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D
124
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Solution
The correct option is A144 First term of the given arithmetic series =1 Second term of the given arithmetic series =3 Third term of the given arithmetic series =5 Fourth term of the given arithmetic series =7 Now, Second term - First term =3−1=2 Third term - Second term =5−3=2 Therefore, common difference of the given arithmetic series is 2. The number of terms of the given A.P. series (n)=12 We know that the sum of first n terms of the Arithmetic Progress, whose first term=a and common difference=d is Sn=n2[2a+(n−1)d]