What is the sum of all 2 digit numbers that leave a remainder of 1 when divided by 2?

2598

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2699

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2800

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2475

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Solution

The correct option is D
2475

The numbers required will be 11, 13, 15, 17, ....... 99

So, the sum of the numbers = $[(\frac{45}{2}) (22 + 88)] = 2475$

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