What is the sum of all 2 digit numbers that leave a remainder of 1 when divided by 4?

1225

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1235

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1245

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1265

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Solution

The correct option is A
1225

The numbers required will be 13, 17, 19, ......

So, the sum of numbers = $[(\frac{22}{2}) (26 + 42)] = 748$

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