Question

What is the sum of all four digit numbers formed by using the digits $2,3,4and5$ without repetition?

• A. $93324$
• B. $92314$
• C. $93024$
• D. $91242$

Answer 1

The correct option is A $93324$

$2,3,4,5$

No repetition

Number of given digits $=n=4$

Sum of digits

$\Rightarrow 2+3+4+5\Rightarrow 14$

Sum of all four digits formed

$\Rightarrow (n-1)!\left(sumofdigits\right)\left(\mathrm{1111....}ntimes\right)\Rightarrow (n-1)!\left(14\right)\left(1111\right)\Rightarrow 3!\times 14\times 1111\Rightarrow 6\times 14\times 1111\Rightarrow 84\times 1111\Rightarrow 93324$

Option $:A$