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Question

What is the sum of all natural numbers between 200 and 400 which are divisible by 7?

A
6729
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B
8712
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C
8729
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D
9276
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Solution

The correct option is C 8729
The numbers lying between 200 and 400, which are divisible by 7 are-
203,210,217,­­­­­­­­399
Therefore,
First term (a)=203
Last term (l)=399
Common difference (d)=7
Let the number of terms of the A.P. be n.
an=399
399=a+(n1)d
399=203+(n1)7
7(n1)=196
n1=28
n=29
S29 =292(203+399)=8729

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