Question

Question 14
What is the sum of all the angles of a pentagon?
a) ${180}^{\circ }$
b) ${360}^{\circ }$
c) ${540}^{\circ }$
d) ${720}^{\circ }$

Answer 1

$\text{We know that, the sum of angles of a polygon}$
$=(n-2)\times {180}^{\circ },$
$\text{where n is the number of sides of the polygon.}$
$\text{In pentagon, n = 5}$
$\therefore \text{Sum of the angles}$
$=(n-2)\times {180}^{\circ }$
$=(5-2)\times {180}^{\circ }$
$=3\times {180}^{\circ }$
$={540}^{\circ }$