What is the sum of all the angles of a triangle?

180^o

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360^o

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90^o

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45^o

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Solution

The correct option is A
180^o

Sum of the angles of a triangle is $180^{\circ}$ .

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Similar questions

45^{o}, 90^{o}, 45^{o}

360^{o}

tan A + cot (180^{o} + A) + cot (90^{o} + A) + cot (360^{o} - A) =

△ A B C, ∠ B = 90^{o}, ∠ A = 45^{o} = ∠ C

sec 45^{o} =

45^{o} - 45^{o} - 90^{o}

\frac{1}{\sqrt{2}}

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