What is the sum of first $100$ consecutive odd numbers?

1 + 2 + 4 + 6 + 8 + 10 + . . . 100 = 12000

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2 + 3 + 4 + 7 + 9 + 11 + . . .100 = 10000

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1 + 3 + 5 + 7 + 10 + 11 + . . . .100 = 1000

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1 + 3 + 5 + 7 + 9 + 11 + . . .100 = 10000

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Solution

The correct option is D $1 + 3 + 5 + 7 + 9 + 11 + . . .100 = 10000$
The sum of first $100$ consecutive odd numbers is $1 + 3 + 5 + 7 + 9 + 11 + . . . . + 100$
Since, we know the formula for sum of consecutive odd numbers $= n^{2}$
So, $n = 100$ , Sum $= (100)^{2} = 10000$

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Question 4

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(10)^{9} + 2 (11)^{1} (10)^{8} + 3 (11)^{2} (10)^{7} + \dots \dots + 10 (11)^{9} = k (10)^{9}

, then k is equal to

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What is the sum of first 100 consecutive odd numbers?

The correct option is D 1+3+5+7+9+11+...100=10000The sum of first 100 consecutive odd numbers is 1+3+5+7+9+11+....+100Since, we know the formula for sum of consecutive odd numbers =n2So, n=100, Sum =(100)2=10000

What is the sum of first $100$ consecutive odd numbers?

The correct option is D $1 + 3 + 5 + 7 + 9 + 11 + . . .100 = 10000$
The sum of first $100$ consecutive odd numbers is $1 + 3 + 5 + 7 + 9 + 11 + . . . . + 100$
Since, we know the formula for sum of consecutive odd numbers $= n^{2}$
So, $n = 100$ , Sum $= (100)^{2} = 10000$