What is the sum of six consecutive odd numbers to form 216?
Given number 216 is the cube of 6, i.e. 63=216.
We know,
1=1=13,
3+5=8=23,
7+9+11=27=33,
13+15+17+19=64=43,
21+23+25+27+29=125=53,
31+33+35+37+39+41=216=63.
∴ The sum of six consecutive odd numbers are to form 216 is 31+33+35+37+39+41=216.
Hence, option D is correct.