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Question

What is the sum of six consecutive odd numbers to form 216?

A
31+33+35+17+39+41
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B
31+33+35+19+39+41
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C
31+33+35+27+39+41
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D
31+33+35+37+39+41
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Solution

The correct option is C 31+33+35+37+39+41

Given number 216 is the cube of 6, i.e. 63=216.


We know,

1=1=13,

3+5=8=23,

7+9+11=27=33,

13+15+17+19=64=43,

21+23+25+27+29=125=53,

31+33+35+37+39+41=216=63.


The sum of six consecutive odd numbers are to form 216 is 31+33+35+37+39+41=216.


Hence, option D is correct.


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