What is the sum of successive odd natural numbers?

n x n

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n / n

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n + n

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0.0

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Solution

The correct option is A n x n

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Similar questions

The sum S of n successive odd numbers starting from 3 is given by the relation : S = n (n + 2). Determine n, if the sum is 168.

(\frac{n}{0})

(\frac{n}{1})

(\frac{n}{2})

(\frac{n}{n})

\frac{n (n + 1)}{2}

\frac{n (n + 1)}{2}

Prove that: 1 + 2 + 3 + ......... + n = $\frac{n (n + 1)}{2}$ i.e., the sum of the first n natural numbers is $\frac{n (n + 1)}{2}$ .

If the sum of first n even natural numbers is equal to k times the sum of the first n odd natural numbers, then k =

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