What is the sum of the coefficients of all the terms in the given expression: 6xy−(x+1)(y)?
The terms in the expression are: 6xy,−(x+1)y
The coefficients of these terms are 6, -1
Their sum = 6 -1 = 5
What are the factors of the terms of the given expression: 6xy−(x+1)(y)?
If the number of terms in the expansion of (1−2x+4x2)n, x≠0 is 28, then the sum of the coefficients of all the terms in this expansion, is :
The sum of all the numerical coefficients including constant, for a given algebraic expression 17x2y - 12xy3 + 31x3 - 37 is