What is the sum of the coefficients of the products for the following reaction, after balancing?
$. . . K_{2} C r_{2} O_{7} + . . . H C l \to . . . K C l + . . . C r C l_{3} + . . . H_{2} O + . . . C l_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 14
Option D is the correct answer.
The balanced equation can be written as-
$K_{2} C r_{2} O_{7}$ $+$ $14 H C l$ $=$ $2 K C l$ $+$ $2 C r C l_{3}$ $+$ $7 H_{2} O$ $+$ $3 C l_{2}$
Thus the sum of the co-efficients of the products totals up to $14$

Suggest Corrections

Similar questions

K_{2} C r_{2} O_{7} + H C l \to K C l + C r C l_{3} + H_{2} O + C l_{2}

. . . K_{2} {C r}_{2} O_{7} + . . . H C l \to . . . K C l + . . . C r {C l}_{3} + . . . H_{2} O + . . . {C l}_{2}

K_{2} C r_{2} O_{7} + H C l \to K C l + C r C l_{3} + H_{2} O + C l_{2}

_{2}

K_{2} C r_{2} O_{7} + H C l

\to K C l + C r C l_{3} + H_{2} O + C l_{2}

H_{2} O

H C l + K M n O_{4} \to H_{2} O + K C l + M n C l_{2} + C l_{2}

Join BYJU'S Learning Program