Question

What is the sum of the factors of $2^4\times 3^3$?

Answer 1

Sum of factors=$\frac{2^5-1}{2-1}\times \frac{3^4-1}{3-1}$

$=\frac{32-1}{1}\times \frac{81-1}{2}$

$=31\times \frac{80}{2}$

$=31\times 40$

$=1240$