What is the surface area of the cuboidal box which is open at the top, if:
$l =$ length of the cuboid,
$b =$ breadth of the cuboid and
$h =$ height of the cuboid

$2 (l b + b h + l h)$

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$2 l b + 2 b h + h l$

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$2 l b + b h + 2 h l$

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$l b + 2 b h + 2 h l$

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Solution

The correct option is D
$l b + 2 b h + 2 h l$

When the cuboidal box is cut open, the total surface area is the sum of the areas of five rectangles as shown in the figure.
Surface Area $= h l + l b + b h + h l + b h$
$\Rightarrow$ Surface Area $= l b + 2 b h + 2 h l$

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Similar questions

The surface area of a box which is in the form of a cuboid whose dimensions are l $\times$ b $\times$ h is:

The total surface area of a box which is in the form of a cuboid whose dimensions are $l \times b \times h$ is _______.

2 (l b + b h + l h)

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