What is the tangential acceleration?

3 α

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2 α

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α

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4 α

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Solution

The correct option is A $2 α$
We have
$s = α t^{2}$
So, $v = \frac{d s}{d t} = 2 α t$
and, $α^{'}$ (tangential acceleration) $= \frac{d v}{d t} = 2 α$

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