What is the temperature at which the kinetic energy of 0.3 moles of helium is equal to the kinetic energy of 0.4 moles of argon at 400 K?
Kinetic Energy of n moles = (3/2)nRT
R = gas constant , T = temperature
⇒ n1T1 = n2T2 or n HeTHe = nArTAr
Put the value of nHe = 0.30 nAr = 0.40 TAr = 400 K in the formula, we get
THe = 533 K
Option C is correct answer