What is the temperature of mixture formed when 5 g of ice at 00 C is placed in 200 g of water at 10- C in a copper calorimeter of heat capacity 25 J -0 C -A- 3-8- CB- 7-8- CC- 4-2- CD- 2-5- CE- 8-7- C

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Standard X

Physics

Change in State

What is the t...

Question

What is the temperature of mixture formed when 5 g of ice at 0⁰C is placed in 200 g of water at 10⁰C in a copper calorimeter of heat capacity 25 J/ ⁰C?

3.8^oC

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7.8^oC

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4.2^oC

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2.5^oC

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8.7^oC

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Solution

The correct option is B
7.8^oC

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Similar questions

A thermos flask contains 100 g of water at 0⁰C & 20 g of ice at 0⁰C. Calculate the temperature of the mixture formed when 50 g of water at 100⁰C is placed in the flask.

Q. A copper calorimeter of mass

100 g m

contains

200 g m

of a mixture of ice and water. Steam at

100^{\circ} C

under normal pressure is passed into the calorimeter and the temperature of the mixture is allowed to rise to

50^{\circ} C

. If the mass of the calorimeter and its contents is now

330 g m

, what was the ratio of ice and water in the beginning? Neglect heat losses.
Given: Specific heat capacity of copper

= 0.42 \times 10^{3} J k g^{- 1} K^{- 1}

,
Specfic heat capacity of water

= 4.2 \times 10^{3} J k g^{- 1} K^{- 1}

Specific heat of fusion of ice

= 3.36 \times 10^{5} J k g^{- 1}

Latent heat of condensation of steam

= 22.5 \times 10^{5} J k g^{- 1}

5 g

of water at

30^{\circ} C

and

5 g

of ice at

- 20^{\circ} C

are mixed together in a calorimeter. Find the final temperature of the mixture. Assume water equivalent of calorimeter to be negligible, specific heats of ice and water are

0.5

and

1 c a l / g^{\circ} C

, and latent heat of ice is

80 c a l / g

A 5g piece of ice at $- 20^{\circ}$ C is put into 10g of water at $30^{\circ}$ C. Assuming that heat is enchanged only between the ice and the water, find the final temperature of the mixture. Specific heat capacity of ice $= 2100 J k g^{- 1}^{\circ} C^{- 1}$ . Specific heat capacity of water $= 4200 J k g^{- 1}^{\circ} C^{- 1}$ and latent heat of fusion of ice $3.36 \times 10^{5} J k g^{- 1}$ .