What is the tens digit of the sum of the first 50 terms of 1, 11, 111, 1111, 11111, 111111, .........?

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Solution

The correct option is B 4

unit digit (1 + 1 .... 50 times) = 0
and carry = 5
tens digit (1 + 1 + .... 49 times) + carry 5 = 4

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Similar questions

1 + 11 + 111 + 1111 + 11111 + . . . . .

9

1^{2} = 1

11^{2} = 121

111^{2} = 12321

1111^{2} = 1234321

11111^{2} = 123454321

111111^{2} =

1111111^{2} =

1, 11, 111, 1111, 11111, . . .

11 \times 11 = 121

111 \times 111 = 12321

1111 \times 1111 = ?

1 \times 9 + 2 = 11 12 \times 9 + 3 = 111 123 \times 9 + 4 = 1111 1234 \times 9 + 5 = 11111 12345 \times 9 + 6 = . . . . . . 123456 \times 9 + 7 = . . . . . .

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